## BdMO National Higher Secondary 2009/8

Discussion on Bangladesh Mathematical Olympiad (BdMO) National
Moon
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### BdMO National Higher Secondary 2009/8

Problem 8:
The region $A$ is bounded by the $x$-axis, the line $y=\frac {x}{2}$ and the ellipse $\frac {x^2}{9}+y^2=1$. The region $B$ is bounded by the $y$-axis, the line $y = mx$ and the ellipse $y=\frac {x}{2}$ and the ellipse $\frac {x^2}{9}+y^2=1$. Find $m$ such that area of region $A$ is the equal to the area of region $B$.
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samiul_samin
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Joined: Sat Dec 09, 2017 1:32 pm

### Re: BdMO National Higher Secondary 2009/8

Moon wrote:
Sun Feb 06, 2011 11:34 pm
Problem 8:
The region $A$ is bounded by the $x$-axis, the line $y=\frac {x}{2}$ and the ellipse $\frac {x^2}{9}+y^2=1$. The region $B$ is bounded by the $y$-axis, the line $y = mx$ and the ellipse $y=\frac {x}{2}$ and the ellipse $\frac {x^2}{9}+y^2=1$. Find $m$ such that area of region $A$ is the equal to the area of region $B$.
Problem source
Putnum 1994 P2