BdMO National Higher Secondary 2009/8
Posted: Sun Feb 06, 2011 11:34 pm
Problem 8:
The region $A$ is bounded by the $x$-axis, the line $y=\frac {x}{2}$ and the ellipse $\frac {x^2}{9}+y^2=1$. The region $B$ is bounded by the $y$-axis, the line $y = mx$ and the ellipse $y=\frac {x}{2}$ and the ellipse $\frac {x^2}{9}+y^2=1$. Find $m$ such that area of region $A$ is the equal to the area of region $B$.
The region $A$ is bounded by the $x$-axis, the line $y=\frac {x}{2}$ and the ellipse $\frac {x^2}{9}+y^2=1$. The region $B$ is bounded by the $y$-axis, the line $y = mx$ and the ellipse $y=\frac {x}{2}$ and the ellipse $\frac {x^2}{9}+y^2=1$. Find $m$ such that area of region $A$ is the equal to the area of region $B$.