Problem 5:
How many regular polygons can be constructed from the vertices of a regular polygon with $2010$ sides? (Assume that the vertices of the $2010$-gon are indistinguishable)
BdMO National Higher Secondary 2010/5
Re: BdMO National Higher Secondary 2010/5
Isn't it 16?
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"When you have eliminated the impossible, whatever remains, however improbable, must be the truth." - Sherlock Holmes
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Nadim Ul Abrar
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Re: BdMO National Higher Secondary 2010/5
isn't it $14$ ?Labib wrote:Isn't it 16?
$2010$ has $14$ divisors$ < 1005$
$\frac{1}{0}$
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bristy1588
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Re: BdMO National Higher Secondary 2010/5
I second Nadim ul abrar, I think the answer should be 14.
@Labib.
2010 has 16 divisors out of which there will be no polygons with side 1 or 2, So i think the answer is 14.
@Labib.
2010 has 16 divisors out of which there will be no polygons with side 1 or 2, So i think the answer is 14.
Bristy Sikder