BdMO National 2021 Junior Problem 5

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Anindya Biswas
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BdMO National 2021 Junior Problem 5

Unread post by Anindya Biswas » Mon Apr 12, 2021 11:47 am

\(1\) থেকে \(19\) বছরবিশিষ্ট উনিশজন শিশু বৃত্তাকারে দাঁড়িয়ে আছে। পাশাপাশি দাঁড়ানো প্রতি জোড়া শিশুর বয়সের পার্থক্যগুলো রেকর্ড করা হলো। এই \(19\)-টা রেকর্ডেড সংখ্যার যোগফলের সম্ভাব্য সর্বোচ্চ মান কত?

Nineteen children, aged $1$ to $19$, respectively, are standing in a circle. The difference between the ages of each pair of adjacent children is recorded. What is the maximum value of the sum of these $19$ recorded numbers?
"If people do not believe that mathematics is simple, it is only because they do not realize how complicated life is."
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Qsolver
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Re: BdMO National 2021 Junior Problem 5

Unread post by Qsolver » Tue Jan 24, 2023 11:14 pm

The maximum value of the sum is = 18 + 2*(17+16+....+8)=18+9*25=225+18=243.

So answer is 243.

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