BdMO National Primary 2011/5 (Junior 2011/1)

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Moon
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BdMO National Primary 2011/5 (Junior 2011/1)

Unread post by Moon » Fri Feb 11, 2011 12:24 pm

Problem 5:
We say that a number has a 'square root' if we find another integer which gives us the first number if multiplied by itself. For example, $4$ has a square root since , but $5$ has no square root. Out of the $100$ numbers from $1$ to $100$, how many integers have square roots?
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Re: BdMO National Primary 2011/5 (Junior 2011/1)

Unread post by ataher.sams » Thu Dec 01, 2011 10:01 pm

Very easy....... {i think}
10
Ataher Sams

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Re: BdMO National Primary 2011/5 (Junior 2011/1)

Unread post by nafistiham » Fri Dec 02, 2011 3:24 pm

@ataher.sams
please, post the way of getting the answer along with it. ;) :) :D

here, we just have to find the largest number smaller or equal to $100$.which is $100$ so the answer will be $\sqrt {100}=10$
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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Re: BdMO National Primary 2011/5 (Junior 2011/1)

Unread post by Arafat » Tue Feb 21, 2012 2:37 pm

\[\sqrt{100}=10\]
Then the numbers are .....\[1^{2},2^{2},3^{2},4^{2},5^{2},6^{2},7^{2},8^{2},9^{2} And 10^{2}\]

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Re: BdMO National Primary 2011/5 (Junior 2011/1)

Unread post by prantick » Sun Jan 11, 2015 1:06 pm

answer is 10

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