Exercise 1.13 [Section 1, BOMC-2011]

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sourav das
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Re: Exercise 1.13 [Section 1, BOMC-2011]

Unread post by sourav das » Mon Oct 31, 2011 10:38 am

Sorry for my typing mistake. :oops:
I edited it now.
I'm very bad in typing....
You spin my head right round right round,
When you go down, when you go down down......
(-$from$ "$THE$ $UGLY$ $TRUTH$" )

sourav das
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Re: Exercise 1.13 [Section 1, BOMC-2011]

Unread post by sourav das » Mon Oct 31, 2011 10:40 am

*Mahi* wrote:Both of the problems uses tricks which are taught in our high school, but that doesn't mean that they are negligible. On the other hand , it is a good thing that you learned and can use those right!
I agree with Mahi
You spin my head right round right round,
When you go down, when you go down down......
(-$from$ "$THE$ $UGLY$ $TRUTH$" )

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*Mahi*
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Re: Exercise 1.13 [Section 1, BOMC-2011]

Unread post by *Mahi* » Mon Oct 31, 2011 10:41 am

sourav das wrote:Sorry for my typing mistake. :oops:
I edited it now.
I'm very bad in typing....
Nope, it wasn't your typing mistake. Notice that $x=0$ makes the LHS of the given inequality undefined.
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sourav das
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Re: Exercise 1.13 [Section 1, BOMC-2011]

Unread post by sourav das » Mon Oct 31, 2011 10:50 am

No, I'm not saying for $x=0$
I'm saying it for writing "missing the part $x \leq -\frac{1}{2}$ "instead of "missing the part $x\geq -\frac{1}{2}$"
But i've edited that part...
You spin my head right round right round,
When you go down, when you go down down......
(-$from$ "$THE$ $UGLY$ $TRUTH$" )

Jini
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Re: Exercise 1.13 [Section 1, BOMC-2011]

Unread post by Jini » Mon Oct 31, 2011 10:56 am

In THIS case, this might actually have a value, you know $\frac{0}{0}$, which is smaller than $\frac{45}{8}$... Like $\frac{sinx}{x}$ tends to one as $x$ tends to zero...
Yay! xD

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Re: Exercise 1.13 [Section 1, BOMC-2011]

Unread post by *Mahi* » Mon Oct 31, 2011 10:58 am

There might be, but we don't actually care about values like $\frac 0 0$s in inequality, and they are left out all the times. I mean, we includes $x \rightarrow 0$ as we have given the limit, but $x=0$ has no meaning, like $\frac {\sin x} x$ has no meaning when $x=0$.
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Re: Exercise 1.13 [Section 1, BOMC-2011]

Unread post by Jini » Mon Oct 31, 2011 11:05 am

Hmmm... Okay...

I have a knack for forgetting to review a problem for further details, very often causing me to make (devastating) silly mistakes. I guess I should try to be more cautious from now on :|
Yay! xD

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