Exercise 1.7 (iii) [Section 1, BOMC-2011]

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sourav das
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Re: Exercise 1.7 (iii) [Section 1, BOMC-2011]

Unread post by sourav das » Mon Oct 31, 2011 4:14 pm

$b\leq 1$ So
$(1+a) \geq b(1+a)$
Now $ 1-ab \geq b-a$
and multiply it with $4ab$
According to your solution i can prove 1>2
1<3
2<3
so, 2-1<0
therefor 1>2
PLEASE PLEASE PLEASE, READ THE FIRST CHAPTER OF THE BOOK AND YOU'LL FIND OUT THAT INEQUALITY IS NOT EQUALITY....
You spin my head right round right round,
When you go down, when you go down down......
(-$from$ "$THE$ $UGLY$ $TRUTH$" )

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