Page 1 of 2
The quadratic function:(BOMC)
Posted: Wed Oct 26, 2011 9:39 am
by sourav das
A quadratic function is in a form of
$f(x)=ax^2 + bx + c$
Any problem and discussion in this section can be done here.
Re: The quadratic function:(BOMC)
Posted: Wed Oct 26, 2011 11:21 am
by TOWFIQUL
Page no 5 isn't printed in my book..!!
Re: The quadratic function:(BOMC)
Posted: Wed Oct 26, 2011 12:51 pm
by *Mahi*
Then get the soft copy of the book.
Re: The quadratic function:(BOMC)
Posted: Wed Oct 26, 2011 3:08 pm
by sm.joty
আমরা বইয়ের পৃষ্ঠা ৬ এর শেষে দেখলাম ,
a>0 হলে নিশ্চায়ক \[\Delta < 0\]
কিন্তু Ez-1.16 এ a>0 আবার \[\Delta > 0\]
ব্যাপারটা কি বুঝলাম না??
Re: The quadratic function:(BOMC)
Posted: Wed Oct 26, 2011 3:22 pm
by sm.joty
Example 1.2.5: (new book):
\[\Delta =[(a^2-b^2-c^2)-4b^2c^2]<0\]
\[\Leftrightarrow [a+b+c][a-b-c][a-b+c]][a+b-c]<0\]
\[\Leftrightarrow [b+c-a][c+a-b][a+b-c]>0\]
এখানে [a+b+c] কোথায় গেল ? বুঝি নাই...।
Re: The quadratic function:(BOMC)
Posted: Wed Oct 26, 2011 5:49 pm
by FahimFerdous
Joty, as a,b,c>0 then (a+b+c) must be positive. They just divided both sides by (a+b+c), that's it.
Re: The quadratic function:(BOMC)
Posted: Wed Oct 26, 2011 5:55 pm
by *Mahi*
sm.joty wrote:
\[\Delta =[(a^2-b^2-c^2)-4b^2c^2]<0\]
\[\Leftrightarrow [a+b+c][a-b-c][a-b+c]][a+b-c]<0\]
\[\Leftrightarrow [b+c-a][c+a-b][a+b-c]>0\]
$[a+b+c][a-b-c][a-b+c]][a+b-c]<0$ is just divided by $-[a+b+c]$ here.
Re: The quadratic function:(BOMC)
Posted: Wed Oct 26, 2011 9:57 pm
by rafid
so where did the minus sign go?
Re: The quadratic function:(BOMC)
Posted: Wed Oct 26, 2011 10:22 pm
by Nadim Ul Abrar
@ রাফিদ ঃ
সহজ বাংলায় মাইনাসে মাইনাসে প্লাস হয়ে গেসে ।।।
ভাল করে -[a+b+c] গুন করার আগে ও পরের তফাতটা দেখ ।।
Re: The quadratic function:(BOMC)
Posted: Wed Oct 26, 2011 10:39 pm
by nafistiham
just like this:
