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### Re: [OGC1] Online Geometry Camp: Day 2

Posted: **Thu Aug 29, 2013 12:22 am**

by **Tusher Chakraborty**

Ayantika rinti bose wrote:Hello,

Actually i am not so sure if you are seeing my solutions or not because you are not replying to me.i was ill so i joined the camp 2 days later,but i have done all the maths from day 1 and also replied 2 you.please atleast send me an email that you are seeing my solutions.and here is the half solution of problem 1 day2.‘half ’ because that is what i could do.

By angle bisector theorem we find that BD/DC=AB/AC.so,AB/DC =root 41/root 164=1/2.so,2BD=DC.

that’s that i could do.BUT PLZ NOTIFY ME IF YOU ARE SEEING MY SOLUTIONS!!!!!

I can't see your solution.

### Re: [OGC1] Online Geometry Camp: Day 2

Posted: **Thu Aug 29, 2013 12:30 am**

by ***Mahi***

Tusher Chakraborty wrote:Ayantika rinti bose wrote:Hello,

Actually i am not so sure if you are seeing my solutions or not because you are not replying to me.i was ill so i joined the camp 2 days later,but i have done all the maths from day 1 and also replied 2 you.please atleast send me an email that you are seeing my solutions.and here is the half solution of problem 1 day2.‘half ’ because that is what i could do.

By angle bisector theorem we find that BD/DC=AB/AC.so,AB/DC =root 41/root 164=1/2.so,2BD=DC.

that’s that i could do.BUT PLZ NOTIFY ME IF YOU ARE SEEING MY SOLUTIONS!!!!!

I can't see your solution.

I think they are in different topics. Here are the total 4 posts you made -

http://www.matholympiad.org.bd/forum/se ... 6&sr=posts . Did you make any other post than these?

### Re: [OGC1] Online Geometry Camp: Day 2

Posted: **Thu Sep 05, 2013 12:18 pm**

by **Swargo**

হি হি হি। আমারও চোরাই পদ্ধতিতে( প্র্যাক্টিক্যাল করে ) ৫.৪ উত্তর আসছে। থিওরিটিক্যালি পারতেসি না।