## [OGC1] Online Geometry Camp: Day 4

Discussion on Bangladesh National Math Camp
*Mahi*
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### Re: [OGC1] Online Geometry Camp: Day 4

$Solution$ $of$ $problem$ $6$:

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$\text{Solution of problem 6}$:
$\text{Solution of problem 6}$

Use $L^AT_EX$, It makes our work a lot easier!

tanmoy
Posts: 289
Joined: Fri Oct 18, 2013 11:56 pm

### Re: [OGC1] Online Geometry Camp: Day 4

$Solution$ $of$ $problem$ $6$:

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$\text{Solution of problem 6}$:
$\text{Solution of problem 6}$
Okay,thanks.
"Questions we can't answer are far better than answers we can't question"

tanmoy
Posts: 289
Joined: Fri Oct 18, 2013 11:56 pm
$\text{solution of problem 2}$:
$YP=YA,\therefore \angle YPA=\angle YAP$.Again,$XA=XQ,\therefore \angle XAQ=\angle XQA$.But $\angle PAY=\angle XAQ.\therefore \angle YPX=\angle XQY$.$\therefore$ $PYXQ$ is cyclic.$\therefore$ By $\text{POWER OF POINT}$,$GY=\frac{GP\times GQ}{GX}=\frac{266\times 255}{190}=357$.$\therefore XY=357-190=167$. 