IMO Shortlist 2005 G6
The median $AM$ of triangle $ABC$ intersects the incircle $\omega$ at $K$ and $L$. The lines through $K$ and $L$ parallel to $BC$ intersects $\omega$ again at $X$ and $Y$. The line $AX$ and $AY$ intersect $BC$ at $P$ and $Q$. Prove that, $BP=CQ$.
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Use $L^AT_EX$, It makes our work a lot easier!
Nur Muhammad Shafiullah | Mahi
Use $L^AT_EX$, It makes our work a lot easier!
Nur Muhammad Shafiullah | Mahi
Re: IMO Shortlist 2005 G6
Hint:
Please read Forum Guide and Rules before you post.
Use $L^AT_EX$, It makes our work a lot easier!
Nur Muhammad Shafiullah | Mahi
Use $L^AT_EX$, It makes our work a lot easier!
Nur Muhammad Shafiullah | Mahi
- Phlembac Adib Hasan
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Re: IMO Shortlist 2005 G6
Yeah, Zhao is always awesome. I proved that lemma (also the whole problem) using projective geometry. This solution is (almost) the same as mine. So no need to post again.