Prove that \[\frac{1}{a^3(b+c)}+\frac{1}{b^3(c+a)}+\frac{1}{c^3(a+b)} \ge \frac{3}{2}\]
so easy, do urself and be more confident
Hints:
Well,here is a shorter solutionHasib wrote:let, $a,b,c$ are positive real number such that $abc=1$ . Prove that $\frac{1}{a^3(b+c)}+\frac{1}{b^3(c+a)}+\frac{1}{c^3(a+b)} \ge \frac{3}{2}$
so easy, do urself and be more confident
Hints: