Yes,I also believe it.Detailed SolutionM. M. Fahad Joy wrote: ↑Tue Feb 20, 2018 5:44 pmThe main object of this forum is to make our students interested in maths. So we should not be bothered but helping each other.

Think about the sum of these numbers

$000$

$001$

$002$

$003$

$004$

$005$

$006$

.

.

.

.

.

$600$

.

.

.

.

$998$

$999$

The sum is

$(1+2+3+4+5+6+7+8+9)×(100+100+100)=45 ×300=13500$... ... ...($1$)

Now as a same manner think about them

$1000$

$1001$

$1002$

$1003$

$1004$

$1005$

$1006$

$1007$

$1008$

$1009$

$1010$

.

.

.

$1699$

.

.

.

$1998$

$1999$

The sum of these numbers $13500+1000=14500$... ... ...($2$)

Now count the numbers from 2000 to 2015,you will get

$(16×2)+1+2+3+4+5+6+7+8+9+(1×6)+1+2+3+4+5=98$... ... ...($3$)

($1$)+($2$ )+($3$)$=13500+14500+98=28098$

I hope it is clear to you now.If not feel free to question.I will not get bothered