Divisional Math Olympiad, Dhaka-2016,primary, ques. 7

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ahsaf
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Divisional Math Olympiad, Dhaka-2016,primary, ques. 7

Unread post by ahsaf » Sat Jan 30, 2016 9:30 pm

I am not able to solve the question. Please help me soon!

x is a two-digit positive number and y is a three digit positive number
The values of x and y is such that if x is added by y % and if y is subtracted by x %, the result will be the same
How many numbers can be replaced with x or y such that the above statement is true???


[[If I have any problem with my question , please let me know ; I will edit soon]]]
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asif e elahi
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Re: Divisional Math Olympiad, Dhaka-2016,primary, ques. 7

Unread post by asif e elahi » Sun Jan 31, 2016 4:03 pm

The condition gives us the equation $x+\frac{y}{100}=y-\frac{x}{100}$. Then prove that $x=99$.

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ahsaf
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Re: Divisional Math Olympiad, Dhaka-2016,primary, ques. 7

Unread post by ahsaf » Fri Feb 05, 2016 11:11 pm

I didn't understand why are we taking $99$ to prove the problem
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asif e elahi
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Re: Divisional Math Olympiad, Dhaka-2016,primary, ques. 7

Unread post by asif e elahi » Fri Feb 05, 2016 11:29 pm

ahsaf wrote:I didn't understand why are we taking $99$ to prove the problem
Because $x$ has the only value $99$.

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M. M. Fahad Joy
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Re: Divisional Math Olympiad, Dhaka-2016,primary, ques. 7

Unread post by M. M. Fahad Joy » Tue Feb 20, 2018 10:54 am

Solve.
X = 99 and Y = 100
Because,
x*y% = 99*100% = 99 and y*x% = 100*99% = 99
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Re: Divisional Math Olympiad, Dhaka-2016,primary, ques. 7

Unread post by samiul_samin » Tue Feb 20, 2018 1:51 pm

M. M. Fahad Joy wrote:
Tue Feb 20, 2018 10:54 am
Solve.
X = 99 and Y = 100
Because,
x*y% = 99*100% = 99 and y*x% = 100*99% = 99
Use LaTeX.It will make your post more readable.

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M. M. Fahad Joy
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Re: Divisional Math Olympiad, Dhaka-2016,primary, ques. 7

Unread post by M. M. Fahad Joy » Tue Feb 20, 2018 10:02 pm

samiul_samin wrote:
Tue Feb 20, 2018 1:51 pm
M. M. Fahad Joy wrote:
Tue Feb 20, 2018 10:54 am
Solve.
X = 99 and Y = 100
Because,
x*y% = 99*100% = 99 and y*x% = 100*99% = 99
Use LaTeX.It will make your post more readable.

Sorry, my answer was wrong. Can you solve this?
You cannot cross the sea merely by standing and staring at the water.

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Re: Divisional Math Olympiad, Dhaka-2016,primary, ques. 7

Unread post by samiul_samin » Thu Mar 01, 2018 10:31 pm

Solution
$X=99$ & $Y=100$
$X×Y\%=99×100\%=99$ and
$Y×X\%=100×99\%=99$
Last edited by samiul_samin on Fri Mar 02, 2018 2:56 pm, edited 1 time in total.

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M. M. Fahad Joy
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Re: Divisional Math Olympiad, Dhaka-2016,primary, ques. 7

Unread post by M. M. Fahad Joy » Fri Mar 02, 2018 12:23 am

samiul_samin wrote:
Thu Mar 01, 2018 10:31 pm
Solution
$X=99$ & $Y=99$
$X×Y\%=99×100\%=99$ and
$Y×X\%=100×99\%=99$
Sorry, you are wrong.
You cannot cross the sea merely by standing and staring at the water.

samiul_samin
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Re: Divisional Math Olympiad, Dhaka-2016,primary, ques. 7

Unread post by samiul_samin » Wed Mar 07, 2018 10:59 pm

M. M. Fahad Joy wrote:
Fri Mar 02, 2018 12:23 am
samiul_samin wrote:
Thu Mar 01, 2018 10:31 pm
Solution
$X=99$ & $Y=99$
$X×Y\%=99×100\%=99$ and
$Y×X\%=100×99\%=99$
Sorry, you are wrong.
It was a typing mistake.I have already fixed that.

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