> Or <???

For students of class 6-8 (age 12 to 14)
sakibtanvir
Posts:188
Joined:Mon Jan 09, 2012 6:52 pm
Location:24.4333°N 90.7833°E
> Or <???

Unread post by sakibtanvir » Thu Jan 26, 2012 1:35 pm

\[99^n+100^n,101^n\] If n>50,then which one is greater?
Last edited by sakibtanvir on Thu Jan 26, 2012 2:54 pm, edited 1 time in total.
An amount of certain opposition is a great help to a man.Kites rise against,not with,the wind.

sourav das
Posts:461
Joined:Wed Dec 15, 2010 10:05 am
Location:Dhaka
Contact:

Re: > Or <???

Unread post by sourav das » Thu Jan 26, 2012 2:04 pm

Please edit it correctly...
You spin my head right round right round,
When you go down, when you go down down......
(-$from$ "$THE$ $UGLY$ $TRUTH$" )

sakibtanvir
Posts:188
Joined:Mon Jan 09, 2012 6:52 pm
Location:24.4333°N 90.7833°E

Re: > Or <???

Unread post by sakibtanvir » Thu Jan 26, 2012 2:54 pm

Slip of Keyboard.. :oops:
An amount of certain opposition is a great help to a man.Kites rise against,not with,the wind.

User avatar
nafistiham
Posts:829
Joined:Mon Oct 17, 2011 3:56 pm
Location:24.758613,90.400161
Contact:

Re: > Or <???

Unread post by nafistiham » Fri Jan 27, 2012 12:43 am

\[101^n=(100+1)^n\]

now use Binomial theorem
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.
Introduction:
Nafis Tiham
CSE Dept. SUST -HSC 14'
http://www.facebook.com/nafistiham
nafistiham@gmail

Post Reply