BDMO NATIONAL Junior 2016/03

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 Location: Rajshahi,Bangladesh
BDMO NATIONAL Junior 2016/03
The problem looks easy and it is but I want to sure I am right .So, i am giving it here......Please give the answer in Bangla..................................There is a simple polygon with 2016 sides where there is intersection among the sides except the intersections of the adjacent sides. Maximum how many diagonals can be drawn inside the polygon such that if any two diagonals intersect , then their of intersection can't be any other point except the vertex of the polygon?

 Posts: 57
 Joined: Sun Dec 11, 2016 2:01 pm
Re: BDMO NATIONAL Junior 2016/03
If we mark our total diagonals as M,we find M=C(2016,2)2016.Then our required diagonals will be less than the total number of diagonals.By cutting out a pattern.....we follow that for an N sided polygon,the required diagonals as per the question is 2n+(n1)+(n2).........+2+1...So,the required number of diagonals=2*2016+2015+2014....+2+1...which is less than C(2016,2)2016
Re: BDMO NATIONAL Junior 2016/03
Total wrong solution.$2 \times 2016 + 2015 + 2014 +......... + 2 + 1 > C(2016,2)  2016.$aritra barua wrote:If we mark our total diagonals as M,we find M=C(2016,2)2016.Then our required diagonals will be less than the total number of diagonals.By cutting out a pattern.....we follow that for an N sided polygon,the required diagonals as per the question is 2n+(n1)+(n2).........+2+1...So,the required number of diagonals=2*2016+2015+2014....+2+1...which is less than C(2016,2)2016
To find the number of required diagonals, just show that the triangulation of the polygon satisfies the number of diagonals.
The study of mathematics, like the Nile, begins in minuteness but ends in magnificence.
 Charles Caleb Colton
 Charles Caleb Colton

 Posts: 57
 Joined: Sun Dec 11, 2016 2:01 pm
Re: BDMO NATIONAL Junior 2016/03
I am wrong indeed......but as I am still in class 8,I don't understand what triangulation of polygon is....

 Posts: 57
 Joined: Sun Dec 11, 2016 2:01 pm
Re: BDMO NATIONAL Junior 2016/03
I think it should have been 2*2013+2012+2011......+3+2+1,because I did not consider the adjacent points in the 1st case