Multiple of 5
- Fahim Shahriar
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How many $8$ digit numbers are there whose sum of digits; is a multiple of $5$?
Name: Fahim Shahriar Shakkhor
Notre Dame College
Notre Dame College
- Phlembac Adib Hasan
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Re: Multiple of 5
Well,you need to take in account the permutations too.Phlembac Adib Hasan wrote:It is zero included partition.
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- nafistiham
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Re: Multiple of 5
What if we start like this,
$10000004$ is the first one.
$10000009$ is the next.
$10000013,10000018,10000022,10000027$
don't we get $2$ in every $10$ ?
$10000004$ is the first one.
$10000009$ is the next.
$10000013,10000018,10000022,10000027$
don't we get $2$ in every $10$ ?
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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Re: Multiple of 5
This observation is so true that it kills the problem in just one linenafistiham wrote: don't we get $2$ in every $10$ ?
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- nafistiham
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Re: Multiple of 5
The truth is that, I posted this 'post' as an observation because I could not find out a rigorous 'chopping' logic after a lot of brain cooking.*Mahi* wrote:This observation is so true that it kills the problem in just one linenafistiham wrote: don't we get $2$ in every $10$ ?
I believe, someone will do that.
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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- kfoozminus
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Re: Multiple of 5
$\frac{99999999-9999999}{10}\cdot2=18000000$
jannatul ferdows jenny
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Re: Multiple of 5
Proof:nafistiham wrote: The truth is that, I posted this 'post' as an observation because I could not find out a rigorous 'chopping' logic after a lot of brain cooking.
I believe, someone will do that.
Let the sum of first 7 digits of the number be $k$. then there will be exactly $2$ numbers between $0-9$ which, when added with $k$, is divisible by $5$.
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- kfoozminus
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Re: Multiple of 5
simple logic: starting with $10000000$, we get $10$ consecutive number as the 'sum of digits' for every $10$ numbers($10000000-10000009$, $10000010-10000019$, ...) and there're two 'multiple of $5$' among any $10$ consecutive numbers.
jannatul ferdows jenny
https://sites.google.com/site/mathprogrammingbooks/
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