Combinatorics

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famim2011
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Combinatorics

Unread post by famim2011 » Sun Feb 03, 2013 11:00 am

When 6 indistinguishable fair coins are
thrown, how many different outcomes are there?

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nafistiham
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Re: Combinatorics

Unread post by nafistiham » Sun Feb 03, 2013 11:14 am

As they are indistinguishable, it should be $6.$
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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A.a.m
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Re: Combinatorics

Unread post by A.a.m » Sun Feb 03, 2013 2:53 pm

I do agree

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*Mahi*
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Re: Combinatorics

Unread post by *Mahi* » Sun Feb 03, 2013 9:18 pm

nafistiham wrote:As they are indistinguishable, it should be $6.$
Check again, like when 2 indistinguishable fair coins are thrown, how many different outcomes are there? $3$, TT, HT, HH
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Fahim Shahriar
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Re: Combinatorics

Unread post by Fahim Shahriar » Mon Feb 04, 2013 12:41 pm

Have a look.
6 Heads, No Tail
5 Heads, 1 Tail
4 Heads, 2 Tails
.........
No Head , 6 Tails

It's $7$. For $n$ indistinguishable fair coins, $(n+1)$ outcomes.
Name: Fahim Shahriar Shakkhor
Notre Dame College

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nafistiham
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Re: Combinatorics

Unread post by nafistiham » Tue Feb 05, 2013 2:05 pm

Fahim Shahriar wrote: It's $7$. For $n$ distinguishable fair coins, $(n+1)$ outcomes.
yes. You are right. So, is mahi. :oops:
now, someone edit that 'in'.
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.
Introduction:
Nafis Tiham
CSE Dept. SUST -HSC 14'
http://www.facebook.com/nafistiham
nafistiham@gmail

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