When 6 indistinguishable fair coins are

thrown, how many different outcomes are there?

## Combinatorics

- nafistiham
**Posts:**829**Joined:**Mon Oct 17, 2011 3:56 pm**Location:**24.758613,90.400161-
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### Re: Combinatorics

As they are indistinguishable, it should be $6.$

\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]

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### Re: Combinatorics

I do agree

### Re: Combinatorics

Check again, like when 2 indistinguishable fair coins are thrown, how many different outcomes are there? $3$, TT, HT, HHnafistiham wrote:As they are indistinguishable, it should be $6.$

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- Fahim Shahriar
**Posts:**138**Joined:**Sun Dec 18, 2011 12:53 pm

### Re: Combinatorics

Have a look.

6 Heads, No Tail

5 Heads, 1 Tail

4 Heads, 2 Tails

.........

No Head , 6 Tails

It's $7$. For $n$ indistinguishable fair coins, $(n+1)$ outcomes.

6 Heads, No Tail

5 Heads, 1 Tail

4 Heads, 2 Tails

.........

No Head , 6 Tails

It's $7$. For $n$ indistinguishable fair coins, $(n+1)$ outcomes.

Name:

Notre Dame College

**Fahim Shahriar Shakkhor**Notre Dame College

- nafistiham
**Posts:**829**Joined:**Mon Oct 17, 2011 3:56 pm**Location:**24.758613,90.400161-
**Contact:**

### Re: Combinatorics

yes. You are right. So, is mahi.Fahim Shahriar wrote: It's $7$. For $n$ distinguishable fair coins, $(n+1)$ outcomes.

now, someone edit that 'in'.

\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]

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