## Prove me wrong

### Re: Prove me wrong

Actually it is undefined. Division is defined as multiplication by inverse, and there is no multiplicative inverse of zero. So division by zero is undefined.

- Abdul Muntakim Rafi
**Posts:**173**Joined:**Tue Mar 29, 2011 10:07 pm**Location:**bangladesh,the earth,milkyway,local group.

### Re: Prove me wrong

I agree with Masum bhai.

$a/b=c$

$a=b c$

Now if you take a and b to be 0 then

$0=0*c$

It is satisfied for any value of c. So we can't determine the value of c here. So it is undetermined.

Again,

$a = b c$

$R= 0* c$

Now if take a to be a any number(except 0) and b to be 0. you can't find any value of c. Its horrible. We can't define c using any of our logic. So its undefined.

$a/b=c$

$a=b c$

Now if you take a and b to be 0 then

$0=0*c$

It is satisfied for any value of c. So we can't determine the value of c here. So it is undetermined.

Again,

$a = b c$

$R= 0* c$

Now if take a to be a any number(except 0) and b to be 0. you can't find any value of c. Its horrible. We can't define c using any of our logic. So its undefined.

**Man himself is the master of his fate...**

### Re: Prove me wrong

Then your first line $a/b$ is undefined (not undetermined). The word undetermined has a very specific meaning; it means something is definable, but cannot determined. You cannot define something else like $a/b$ where $b \neq 0$ and then take $b = 0$.Abdul Muntakim Rafi wrote:I agree with Masum bhai.

$a/b=c$

$a=b c$

Now if you take a and b to be 0 then

- Abdul Muntakim Rafi
**Posts:**173**Joined:**Tue Mar 29, 2011 10:07 pm**Location:**bangladesh,the earth,milkyway,local group.

### Re: Prove me wrong

Bhaiya, we can't define $x/0$ where x is not equal to 0.

but we can define $0/0$

The above process proves that... Yet we can't determine the value... so $indeterminate$ ...

Maybe the convention is to use the term $indeterminate$... However, I meant $indeterminate$ by $undetermined$....

but we can define $0/0$

The above process proves that... Yet we can't determine the value... so $indeterminate$ ...

Maybe the convention is to use the term $indeterminate$... However, I meant $indeterminate$ by $undetermined$....

**Man himself is the master of his fate...**

### Re: Prove me wrong

The above process is wrong.Abdul Muntakim Rafi wrote:Bhaiya, we can't define $x/0$ where x is not equal to 0.

but we can define $0/0$

The above process proves that...

### Re: Prove me wrong

Lets start from definitions.

Multiplicative inverse: The multiplicative inverse of a number $x$ is a number $y$ such that $xy=1$.

Division: The division of a number $x$ by a number $y$ is $xy^{-1}$ where $y^{-1}$ is the multiplicative inverse of $y$.

So you see dividing by $0$ is not defined because it has no multiplicative inverse.

Multiplicative inverse: The multiplicative inverse of a number $x$ is a number $y$ such that $xy=1$.

Division: The division of a number $x$ by a number $y$ is $xy^{-1}$ where $y^{-1}$ is the multiplicative inverse of $y$.

So you see dividing by $0$ is not defined because it has no multiplicative inverse.

### Re: Prove me wrong

We usually write the multiplicative inverse of $x$ as $1/x$.

You process is wrong because you first write $a/b$ which actually means $a \times \frac{1}{b}$. Now you cannot take $b=0$ because there is no such thing as $1/0$.

You process is wrong because you first write $a/b$ which actually means $a \times \frac{1}{b}$. Now you cannot take $b=0$ because there is no such thing as $1/0$.

- Abdul Muntakim Rafi
**Posts:**173**Joined:**Tue Mar 29, 2011 10:07 pm**Location:**bangladesh,the earth,milkyway,local group.

### Re: Prove me wrong

Why $0$ doesn't have any multiplicative inverse?

**Man himself is the master of his fate...**

### Re: Prove me wrong

Look at the definition. Is it possible for $0$ to have a multiplicative inverse?

### Re: Prove me wrong

But I think definitions as usual makes not that much sense in real. If $\frac10$ was real, it must be a real number, say it is $x$. Then we could say, \[x.0=1\]

But that is impossible for any $x\in\mathbb R$. So, it never can be a real number. Hope it makes a better sense.

But that is impossible for any $x\in\mathbb R$. So, it never can be a real number. Hope it makes a better sense.

One one thing is neutral in the universe, that is $0$.