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### Re: 3 problems of probability

Posted: **Sun Dec 11, 2011 1:12 am**

by **Abdul Muntakim Rafi**

According to the given info, Tiham's answer is correct...

And probability of aiming something perfectly $9/10$ doesn't mean that if u will shoot the target the 9 out of 10 times... We can only say numbers of hitting the target will be near 9... And as much as you aim for the target($n$) the number of times you hit the target will be near $(9/10)*n$

### Re: 3 problems of probability

Posted: **Sun Dec 11, 2011 7:16 am**

by **jhal_muri**

the results do not depend on previous results anyway.if u toss 2 coins and the first one gives a tail,then there is still 50/ chance for the 2nd coin to give a head as it is not effected.

### Re: 3 problems of probability

Posted: **Sun Dec 11, 2011 2:01 pm**

by **nafistiham**

yap, that's right.because that coin has two sides.

like that, if you wanna count the percentage of passing you can say one can have $1-100$ marks. he will pass if he gets at least $33$.so the probability will be $\frac {33}{100}$

but, saying that, there is many things which you can not defind by sides or marks.on that case you have to depend on the previous happenings

this is not correct.see the next post for correction

### Re: 3 problems of probability

Posted: **Sun Dec 11, 2011 8:04 pm**

by **amlansaha**

Tiham, passing percentage is $\frac{68}{101}$, cause there are 101 numbers(0-100) u can get and 68 numbers(33-100) which will make u pass. so ans to ques no. 1 is $\frac{68}{101}$

### Re: 3 problems of probability

Posted: **Sun Dec 11, 2011 9:16 pm**

by **nafistiham**

### Re: 3 problems of probability

Posted: **Mon Mar 12, 2018 10:34 pm**

by **Mathlomaniac**

Answer of first and second would be 11/12