divide it
Posted: Thu Dec 27, 2012 6:38 pm
show that the number abbcca is divided by 11 for any value of a,b,c within 1-9
I think this statement is incorrect. For a counter example is $211332$ where $a=2,b=1,c=3$.Rafe wrote:show that the number abbcca is divided by 7 for any value of a,b,c within 1-9
Again,with the criteria of divisibility by $7$, we can also show that the first number $abbcca$ is dividible by $7$, if the number $3c-2a-b$ is divisible by $7$. That's how I find examples like $7|211442$ and counter-example $211332$.Fahim Shahriar wrote:The statement is not true at all. If you said $abcabc$, then it would be divisible by $7$.
$a-b+b-c+c-a=0\equiv 0(\bmod \; 11)$ so by the divisibility rule of $11$ we can conclude that $(abbcca)_{10}\equiv 0(\bmod \; 11)$Rafe wrote:show that the number abbcca is divided by 11 for any value of a,b,c within 1-9