## divide it

### Re: divide it

I think this statement is incorrect. For a counter example is $211332$ where $a=2,b=1,c=3$.Rafe wrote:show that the number abbcca is divided by 7 for any value of a,b,c within 1-9

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- Fahim Shahriar
**Posts:**138**Joined:**Sun Dec 18, 2011 12:53 pm

### Re: divide it

The statement is not true at all. If you said $abcabc$, then it would be divisible by $7$.

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Notre Dame College

**Fahim Shahriar Shakkhor**Notre Dame College

### Re: divide it

Again,with the criteria of divisibility by $7$, we can also show that the first number $abbcca$ is dividible by $7$, if the number $3c-2a-b$ is divisible by $7$. That's how I find examples like $7|211442$ and counter-example $211332$.Fahim Shahriar wrote:The statement is not true at all. If you said $abcabc$, then it would be divisible by $7$.

$\color{blue}{\textit{To}} \color{red}{\textit{ problems }} \color{blue}{\textit{I am encountering with-}} \color{green}{\textit{AVADA KEDAVRA!}}$

### Re: divide it

sorry friends.i have corrected that

- Phlembac Adib Hasan
**Posts:**1016**Joined:**Tue Nov 22, 2011 7:49 pm**Location:**127.0.0.1-
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### Re: divide it

$a-b+b-c+c-a=0\equiv 0(\bmod \; 11)$ so by the divisibility rule of $11$ we can conclude that $(abbcca)_{10}\equiv 0(\bmod \; 11)$Rafe wrote:show that the number abbcca is divided by 11 for any value of a,b,c within 1-9

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