Trigonometric Proof
Posted: Sat Jan 12, 2013 6:38 pm
Hello! This is my first post on this wonderful forum, and I hope one of many more to come.
Here is the first question to be posed:
Prove, in as elegant a manner as possible, that
\[\sin x = 2^n \cdot \cos \frac {x}{2} \cdot \cos \frac{x}{x^2} \cdot \cdot \cdot \cos \frac {x}{2^n} \cdot \sin \frac{x}{2^n} \].
Here is the first question to be posed:
Prove, in as elegant a manner as possible, that
\[\sin x = 2^n \cdot \cos \frac {x}{2} \cdot \cos \frac{x}{x^2} \cdot \cdot \cdot \cos \frac {x}{2^n} \cdot \sin \frac{x}{2^n} \].