Functional Equation (Canada 1969)

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Re: Functional Equation (Canada 1969)

Unread post by *Mahi* » Mon Sep 22, 2014 8:13 am

No. The three conditions
$f:\mathbb N \mapsto \mathbb N, f(mn)=f(m)f(n)$
$f$ strictly increasing.
$f(2)=2$ imply the unique solution $f(n)=n$.
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