BdMO 2020 Higher Secondary Preliminary P6

For students of class 11-12 (age 16+)
saifmd
Posts:15
Joined:Wed Feb 24, 2021 12:41 am
BdMO 2020 Higher Secondary Preliminary P6

Unread post by saifmd » Fri Feb 26, 2021 11:32 am

Find the smallest positive integer n such that n! is divisible by 2020 without any remainders.
সবচেয়ে ছোট ধনাত্মক পূর্ণসংখ্যা নির্ণয় কর 2020 দ্বারা n! নিঃশেষে বিভাজ্য হয়।

User avatar
Anindya Biswas
Posts:264
Joined:Fri Oct 02, 2020 8:51 pm
Location:Magura, Bangladesh
Contact:

Re: BdMO 2020 Higher Secondary Preliminary P6

Unread post by Anindya Biswas » Mon Mar 01, 2021 4:02 pm

$2020=2^2\cdot5\cdot101$
So, $n=101$
"If people do not believe that mathematics is simple, it is only because they do not realize how complicated life is."
John von Neumann

User avatar
Mehrab4226
Posts:230
Joined:Sat Jan 11, 2020 1:38 pm
Location:Dhaka, Bangladesh

Re: BdMO 2020 Higher Secondary Preliminary P6

Unread post by Mehrab4226 » Tue Mar 02, 2021 12:12 am

Anindya Biswas wrote:
Mon Mar 01, 2021 4:02 pm
$2020=2^2\cdot5\cdot101$
So, $n=101$
Probably the shortest solution, I have ever seen. :) :)
The Mathematician does not study math because it is useful; he studies it because he delights in it, and he delights in it because it is beautiful.
-Henri Poincaré

saifmd
Posts:15
Joined:Wed Feb 24, 2021 12:41 am

Re: BdMO 2020 Higher Secondary Preliminary P6

Unread post by saifmd » Thu Mar 04, 2021 12:24 pm

Anindya Biswas wrote:
Mon Mar 01, 2021 4:02 pm
$2020=2^2\cdot5\cdot101$
So, $n=101$
A wonderful solution! Thanks a lot.

Post Reply