10 based log

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Abdul Muntakim Rafi
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10 based log

Unread post by Abdul Muntakim Rafi » Wed Apr 20, 2011 10:41 am

1.$log 1$ +$log 2$+$log 3$+...........+$log 100$=? Here the base is 10.
2.In k based log what is the answer?

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*Mahi*
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Re: 10 based log

Unread post by *Mahi* » Fri Apr 22, 2011 1:00 pm

Part 1: $log_{10} 100!$ The decimal representation is too big.
Please make the second part clear
Last edited by *Mahi* on Fri Apr 22, 2011 6:30 pm, edited 1 time in total.
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Abdul Muntakim Rafi
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Re: 10 based log

Unread post by Abdul Muntakim Rafi » Fri Apr 22, 2011 5:22 pm

can u please tell me how you did it?i want an explanation.and the second part asks if there can be found a general method for any base such as 1,2,3,..........,k
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*Mahi*
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Re: 10 based log

Unread post by *Mahi* » Fri Apr 22, 2011 6:27 pm

By the general rules of log, $log_k m+ log_k n=log_k mn $
And the second part is the same , $log_k 100!$
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Abdul Muntakim Rafi
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Re: 10 based log

Unread post by Abdul Muntakim Rafi » Thu Apr 28, 2011 9:24 pm

I cannot believe I picked such an easy question.I was looking for a question to post on the forum.I went to a group and posted it from there.But I was such a fool that I didn't think about it.However,thank u for the answer.
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tarek like math
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Re: 10 based log

Unread post by tarek like math » Thu Apr 28, 2011 9:35 pm

100! has 24 zero in it's last so $100!=a.10^(24)$. $log100!=loga.10^(24)$ then?

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