A circle intersects a square at 8 distinct points. Prove that the sum of the areas of the circle that lies outside the square and the sum of areas of the square which lies outside the square are equal.
Pls. Solve it Quickly. I need it ASAP!
Solve it Quick : Circles and Squares..
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bristy1588
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Bristy Sikder
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sourav das
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Re: Solve it Quick : Circles and Squares..
Please recheck your problem, my Geogebra is clearly showing that it's false.
You spin my head right round right round,
When you go down, when you go down down......(-$from$ "$THE$ $UGLY$ $TRUTH$" )
When you go down, when you go down down......(-$from$ "$THE$ $UGLY$ $TRUTH$" )
Re: Solve it Quick : Circles and Squares..
Well,my question is: Isn't it the sum of the areas of the square that lies outside the circle in the last line?
$\color{blue}{\textit{To}} \color{red}{\textit{ problems }} \color{blue}{\textit{I am encountering with-}} \color{green}{\textit{AVADA KEDAVRA!}}$