Congruence

For discussing Olympiad level Geometry Problems
badass0
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Congruence

Unread post by badass0 » Sat Mar 14, 2015 8:31 pm

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$ABCDEF$ is a regular hexagon. $H$ and $G$ are midpoints of $AB$ and $ED$. Prove,\[ \triangle AFE \cong \triangle AEM \cong \triangle BMD \cong \triangle BCD \] and \[ \triangle AHM \cong \triangle BHM \cong \triangle DMG \cong \triangle EMG \cong \triangle AKF \cong \triangle IEF \cong \triangle CLB \cong \triangle CJD\]

I want hints rather than the solution :D :D
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nayel
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Re: Congruence

Unread post by nayel » Sat Mar 21, 2015 7:23 pm

Hint:
There is too much symmetry here.
"Everything should be made as simple as possible, but not simpler." - Albert Einstein

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