Math help!!!

For discussing Olympiad Level Number Theory problems
Mathlover
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Joined:Thu May 12, 2011 6:05 pm
Math help!!!

Unread post by Mathlover » Tue May 17, 2011 11:44 am

someone plz help me with this math problem-
Find three consecutive odd whole numbers such that sum of squares is a four digit number whose digits are all same.

tarek like math
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Joined:Fri Feb 18, 2011 11:30 pm

Re: Math help!!!

Unread post by tarek like math » Fri May 20, 2011 12:08 am

the possible 4 digits numbers are 1111,3333,5555,7777,9999.(sum of 3 odd squares is an odd number)

tarek like math
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Joined:Fri Feb 18, 2011 11:30 pm

Re: Math help!!!

Unread post by tarek like math » Fri May 20, 2011 12:29 am

i find these three numbers.it's $(41)^2+(43^2)+(45)^2=5555$.
i find it in this method $(2n-1)^2+(2n+1)^2+(2n+3)^2=12(n^2+n+1)-1$. it means the $4$ digit number$+1$ is divisible by $12$ then i try $1112,3334,5556...$ etc.

photon
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Re: Math help!!!

Unread post by photon » Fri May 20, 2011 9:45 am

Try not to become a man of success but rather to become a man of value.-Albert Einstein

Mathlover
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Joined:Thu May 12, 2011 6:05 pm

Re: Math help!!!

Unread post by Mathlover » Sat May 21, 2011 9:07 pm

thanks tarek!!

geeknick
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Joined:Sat Nov 05, 2011 6:39 pm

Re: Math help!!!

Unread post by geeknick » Fri Nov 11, 2011 11:48 am

I heard that tutorvista math offers online help for mathematics. Does anyone know the exact website? Thanx in advance.



I am really struggling with it.

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