A theorem for fun

For discussing Olympiad Level Number Theory problems
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afif mansib ch
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Re: A theorem for fun

Unread post by afif mansib ch » Thu Sep 08, 2011 11:04 pm

thanks via.

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afif mansib ch
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Re: A theorem for fun

Unread post by afif mansib ch » Sat Sep 10, 2011 2:10 pm

thanks :mrgreen:

photon
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Re: A theorem for fun

Unread post by photon » Sat Sep 10, 2011 3:50 pm

it's wrong.you see,$3^5\not\equiv3(mod14)$ while $a=1,b=2,c=7$.
that $(2a+1)^{2b}-1$ is in form $(odd)^2-1$ which is divisible by $8$,not by $2c$.as we don't know what is $c$ so we can't say so.
Try not to become a man of success but rather to become a man of value.-Albert Einstein

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