Excuse me,can u solve me?
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Find all non negative integral solution of the equation
$2^x + 3^y=z^2$
$2^x + 3^y=z^2$
- Tahmid Hasan
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Re: Excuse me,can u solve me?
Hint:take $\pmod 8$,or to kill directly use Zsigmondy's theorem.
বড় ভালবাসি তোমায়,মা
Re: Excuse me,can u solve me?
Please read Forum Guide and Rules before you post.
Use $L^AT_EX$, It makes our work a lot easier!
Nur Muhammad Shafiullah | Mahi
Use $L^AT_EX$, It makes our work a lot easier!
Nur Muhammad Shafiullah | Mahi
- Phlembac Adib Hasan
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Re: Excuse me,can u solve me?
Tahmid vai,there is a easy solution.Check this trick:
viewtopic.php?f=14&t=1911
viewtopic.php?f=14&t=1911
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- Tahmid Hasan
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Re: Excuse me,can u solve me?
Actually I did it that way and Adib,(আদীব) I am thankful to you for teaching me this technique.I first saw it when you solved a problem given by Masum vaiya:$11^a+7^b=k^2$ has no solution,but I have to play a little with congruences to show the exponentials are even<don't I?
বড় ভালবাসি তোমায়,মা
Re: Excuse me,can u solve me?
My solution:
Last edited by sourav das on Mon Apr 23, 2012 9:03 pm, edited 1 time in total.
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Re: Excuse me,can u solve me?
Can anyone tell me how can it be solved by Zsigmondy's theorem?
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Re: Excuse me,can u solve me?
@Xenon,$x=4,y=2,z=5$ is a solution
Last edited by sourav das on Mon Apr 23, 2012 9:05 pm, edited 1 time in total.
Reason: \[L_AT^EXed\]
Reason: \[L_AT^EXed\]
Re: Excuse me,can u solve me?
আমি একটা সিদ্ধান্ত নিতে ভুল করসিলাম। $2^{x_1-1}-1=1$ .সুতরাং $x_1=2$ ,তাই $x=4$,আর $y_1=1$ ফলে $y=2$ আর $z=5$.
Your defense shatters;
The life bar drains to red, then...
Nothing. Game over.
The life bar drains to red, then...
Nothing. Game over.
- zadid xcalibured
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Re: Excuse me,can u solve me?
@xenon,প্রবলেম সল্ভিং এর সময় তাড়াহুড়া করবানা।এইটা অলিম্পিয়াডে অনেক ক্ষতি করতে পারে।মাথা ঠান্ডা রেখে ধীরে সুস্থে চিন্তা করতে হবে,আর প্রবলেমে কি কি শর্ত আছে তা খেয়াল করতে হবে।আর তুমি যখন কোন সমীকরন থেকে সমাধান বের করবা লজিক দিয়ে তখন এক্সসেপশনাল কেইস গুলা বাদ দিতে হবে চিন্তা করে।