divisibility again....:)

For discussing Olympiad Level Number Theory problems
the arrivals
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divisibility again....:)

Unread post by the arrivals » Fri Jan 14, 2011 8:47 am

what you think about the statemen?
1) 3 does divide (n^2+1)....?
give your proof please...
;)
women of purity are for men of purity and hence men of purity are for women of purity - THE HOLY QURAN

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Masum
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Re: divisibility again....:)

Unread post by Masum » Fri Jan 14, 2011 7:28 pm

This means $n^2\equiv -1(mod\ 3)$,contradiction
One one thing is neutral in the universe, that is $0$.

the arrivals
Posts: 41
Joined: Tue Dec 21, 2010 10:17 pm

Re: divisibility again....:)

Unread post by the arrivals » Fri Jan 14, 2011 8:11 pm

you got the right answer sir
women of purity are for men of purity and hence men of purity are for women of purity - THE HOLY QURAN

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Masum
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Re: divisibility again....:)

Unread post by Masum » Sun Jan 16, 2011 10:35 pm

Sir?Who is that?
One one thing is neutral in the universe, that is $0$.

photon
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Re: divisibility again....:)

Unread post by photon » Wed Feb 09, 2011 9:02 am

If n isn't divisible by 3,then the remainder of its squre by 3 will be 1.
So it isn't possible.
Try not to become a man of success but rather to become a man of value.-Albert Einstein

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