minimum value

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jagdish
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minimum value

Unread post by jagdish » Sat May 28, 2011 3:04 pm

Calculate minimum value of $\displaystyle f(x)=\frac{x^4+x^2+1}{(x+1)^2}$

Without using calculus
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Tahmid Hasan
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Re: minimum value

Unread post by Tahmid Hasan » Sat May 28, 2011 8:11 pm

what is the domain?
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jagdish
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Re: minimum value

Unread post by jagdish » Thu Jun 02, 2011 9:43 pm

Here Domain is $x\in\mathbb{R}-\left\{-1\right\}$
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Mehfuj Zahir
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Re: minimum value

Unread post by Mehfuj Zahir » Fri Jun 03, 2011 10:48 am

using calculus is straight forward and dy/dx=0 for for minimum and maximum value

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Moon
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Re: minimum value

Unread post by Moon » Fri Jun 03, 2011 10:25 pm

I don't think that there is a 'nice' answer to the problem. This minimum value is approximately $0.58018100122059$.
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