Calculate minimum value of $\displaystyle f(x)=\frac{x^4+x^2+1}{(x+1)^2}$
Without using calculus
minimum value
jagdish
- Tahmid Hasan
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Re: minimum value
using calculus is straight forward and dy/dx=0 for for minimum and maximum value
Re: minimum value
I don't think that there is a 'nice' answer to the problem. This minimum value is approximately $0.58018100122059$.
"Inspiration is needed in geometry, just as much as in poetry." -- Aleksandr Pushkin
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Please install LaTeX fonts in your PC for better looking equations,
learn how to write equations, and don't forget to read Forum Guide and Rules.