Prove that, for $a+b+c=1$,
\[ \sum_{a,b,c}{\left(\frac{2}{a^{2}}+\frac{7}{a}\right)}\ge 9+\frac{4}{abc} \]
a + b + c = 1
For discussing Olympiad Level Algebra (and Inequality) problems
Unread post by Corei13 » Tue Dec 21, 2010 11:02 pm
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