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f(x)=?

Posted: Tue Mar 21, 2017 9:26 pm
by Thamim Zahin
Find all functions $f:Q \rightarrow Q$ such that
\[f(1)=2\]
and
\[f(xy)=f(x)f(y)−f(x+y)+1\]

Re: f(x)=?

Posted: Thu Mar 23, 2017 12:27 am
by Zawadx
This can be solved by the basic arguments used to solve Cauchy's FE over Q. Try it yourself!

Hint if you're extremely desperate:
$$ f( n + \frac{1}{m}) = n + f( \frac{1}{m} ) $$