Let $ x, y, z$ be positive real numbers so that $ xyz = 1$. Prove that
\[ \left( x - 1 + \frac 1y \right) \left( y - 1 + \frac 1z \right) \left( z - 1 + \frac 1x \right) \leq 1.
\]
Inequality with abc = 1
- asif e elahi
- Posts:185
- Joined:Mon Aug 05, 2013 12:36 pm
- Location:Sylhet,Bangladesh
- Atonu Roy Chowdhury
- Posts:64
- Joined:Fri Aug 05, 2016 7:57 pm
- Location:Chittagong, Bangladesh
Re: Inequality with abc = 1
My solution. Same as Asif Bhai's.
This was freedom. Losing all hope was freedom.
Re: Inequality with abc = 1
Good solution Atonu!