Minimum value
Posted: Sat Jul 22, 2017 3:18 pm
Determine the minimum value of
$\frac{4x^3}{y}+\frac{y+1}{x}$
with $x>0$ and $y>0$ real numbers.
$\frac{4x^3}{y}+\frac{y+1}{x}$
with $x>0$ and $y>0$ real numbers.
I don't think so. Bcoz, x>0 and y>0 are real numbers not natural.Ragib Farhat Hasan wrote: ↑Thu Sep 27, 2018 7:31 pmApparently, the denominators should be 1. So the minimum value will be 6.
I know the difference.NABILA wrote: ↑Mon Dec 17, 2018 6:11 pmI don't think so. Bcoz, x>0 and y>0 are real numbers not natural.Ragib Farhat Hasan wrote: ↑Thu Sep 27, 2018 7:31 pmApparently, the denominators should be 1. So the minimum value will be 6.