Hey! There is a 'JHAMELA'

For discussing Olympiad Level Algebra (and Inequality) problems
NABILA
Posts: 28
Joined: Sat Dec 15, 2018 5:19 pm
Location: Munshigonj, Dhaka

Hey! There is a 'JHAMELA'

Unread post by NABILA » Sat Dec 15, 2018 6:53 pm

If, a=b
Then,
a^2=ab
=>a^2-b^2=a^2-ab
=>(a+b)(a-b)=a(a-b)
=>a+b=a
=>a+a=a
=>2a=a
=>2=1
I know there is a mistake in this calculation. What's that and please give me a logic behind that mistake. :geek:

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samiul_samin
Posts: 1007
Joined: Sat Dec 09, 2017 1:32 pm

Re: Hey! There is a 'JHAMELA'

Unread post by samiul_samin » Thu Jan 10, 2019 12:12 am

NABILA wrote:
Sat Dec 15, 2018 6:53 pm
If, a=b
Then,
a^2=ab
=>a^2-b^2=a^2-ab
=>(a+b)(a-b)=a(a-b)
=>a+b=a
In the last line you divided by zero (as $a=b$).
It is not defined in Mathmatics.Thats the mistke.
Use latex to write mathematical equations.

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