OH!.......Parellelograms

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Phlembac Adib Hasan
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OH!.......Parellelograms

Unread post by Phlembac Adib Hasan » Fri Feb 24, 2012 10:37 am

( Inspired from Masum Vaia ) In co-ordinate plane, join points

$[(0,0),(m,0)],[(0,1),(m,1)],...,[(o,n),(m,n)]$ and

$[(0,0],(0,n)], [(1,0),(1,n)...,[(m,0),(m,n)]$.How many parallelograms can you make

joining the intersection points of these lines?


Note:$(0,0),(2,1),(3,3),(1,2)$ is also a parallelogram.So you must count this type of parallelograms too!

:twisted:
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Re: OH!.......Parellelograms

Unread post by nafistiham » Fri Feb 24, 2012 2:52 pm

let me share a hint given by the topic owner [without permission :twisted: :lol: ]
a parallelogram needs just two pairs of parallel lines, try combinatorics.
[the topic owner does not want you to read it :oops: ]
Last edited by nafistiham on Fri Feb 24, 2012 8:54 pm, edited 1 time in total.
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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Re: OH!.......Parellelograms

Unread post by Phlembac Adib Hasan » Fri Feb 24, 2012 4:50 pm

Not Fare. :evil:
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Re: OH!.......Parellelograms

Unread post by nafistiham » Fri Feb 24, 2012 8:53 pm

Phlembac Adib Hasan wrote:Not Fare. :evil:
ok.i am hiding that.
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.
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Re: OH!.......Parellelograms

Unread post by Phlembac Adib Hasan » Sat Feb 25, 2012 11:46 am

Ok.Ok.It's alright now. :D
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Re: OH!.......Parellelograms

Unread post by nafistiham » Sat Feb 25, 2012 3:24 pm

my solution was like this
\[\sum_{k=1}^{n-1}k \cdot\sum_{p=1}^{m-1}p\]

adib made it short :D :D
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.
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Re: OH!.......Parellelograms

Unread post by Phlembac Adib Hasan » Sat Feb 25, 2012 8:38 pm

nafistiham vaia wrote:my solution was like this
\[\sum_{k=1}^{n-1}k \cdot\sum_{p=1}^{m-1}p\]

adib made it short :D :D
You might do a mistake.Because you are not counting $(0,0),(2,1),(3,3),(1,2)$ type parallelograms,only counting the rectangles.
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