(1)Claudia wants to use $8$ indistinguishable red beads and $32$ indistinguishable blue beads to make a necklace such that there are at least $2$ blue beads between any $2$ red beads.In how many ways can she do this
(2)In how many ways can $8$ girls and $25$ boys be arranged around a circular table so that there are at least $2$ boys between any $2$ girls (China $1990$)
[The above two problems are related.I have solved these.But I have confusion about my solution.So,I am posting these.]
Two problems of circular permutations
Two problems of circular permutations
"Questions we can't answer are far better than answers we can't question"
Re: Two problems of circular permutations
Could anyone post the solutions,please?
"Questions we can't answer are far better than answers we can't question"

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Re: Two problems of circular permutations
not sure the ans is 9!