Two blocks, one with mass of 9kg and another with mass of 3kg, are placed on a frictionless surface touching each other. Now 24N force is applied horizontally on the bigger block.
Determine the magnitude of the action-reaction force between the blocks.
Action-Reaction
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Fahim Shahriar
- Posts:138
- Joined:Sun Dec 18, 2011 12:53 pm
Name: Fahim Shahriar Shakkhor
Notre Dame College
Notre Dame College
Re: Action-Reaction
I think, action and reaction force will be equal between the two blocks.[Newton's Third Law] Their magnitude will be $24 N$, but their accelerations will be different.
Re: Action-Reaction
Let the action-reaction forces between the objects be R each, and their acceleration be a.
For the bigger block, 24 - R = 9a ... ... (1), since two forces are acting upon it.
For the smaller block, R = 3a ... ... ... (2), since only R is acting on it
Solving these, you get all you need.
Note: you do not need to consider the weight force and surface normal force for each object beacuse they cancel each other.
For the bigger block, 24 - R = 9a ... ... (1), since two forces are acting upon it.
For the smaller block, R = 3a ... ... ... (2), since only R is acting on it
Solving these, you get all you need.
Note: you do not need to consider the weight force and surface normal force for each object beacuse they cancel each other.