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ABOUT HCl

Posted: Sun Feb 26, 2012 12:55 pm
by MATHPRITOM
Let, we have taken $ 10^{-9} $ M HCl. now, $ pH=-(log [H^{+}]).=-(log 10^{-9})=-(-9)log 10=9 $ . & We know that pH greater than 7 are base. but, HCl is acid ?? so, what is the problem ??

Re: ABOUT HCl

Posted: Sun Feb 26, 2012 1:15 pm
by Moon
Remember that in an aquas solution you already have $[H^+]=10^{-7}$. You can't make it less than that. :P