If we apply time expansion formula of theory of relativity on Light to detemine how long has it travelled according to our time than what'll I get ?

I cant figure it out

## Age of Light

- Dipta Akash Roy
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- nafistiham
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### Re: Age of Light

as much as i know, time doesn't exist for light.

what do you mean by "our time" ?

what do you mean by "our time" ?

\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]

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### Re: Age of Light

Yeah, your question is not clear to me. If you mean

Also light's frame is not quite well defined, because if light is moving at speed $c$ with respect to me, then that will mean I am moving with speed $c$ with respect to light's frame, but nothing can actually attain that speed.

**in a certain frame**how much time has elapsed for light to travel a distance $d$ then it is simply $t=d/c$.Also light's frame is not quite well defined, because if light is moving at speed $c$ with respect to me, then that will mean I am moving with speed $c$ with respect to light's frame, but nothing can actually attain that speed.

"Inspiration is needed in geometry, just as much as in poetry." -- Aleksandr Pushkin

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**install LaTeX fonts**in your PC for better looking equations,**learn****how to write equations**, and**don't forget**to read Forum Guide and Rules.- Dipta Akash Roy
**Posts:**11**Joined:**Tue Jan 10, 2012 11:09 pm-
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### Re: Age of Light

I meant in the reference frame where I'm stable and light is moving at C.

Well, we determine the travel time of moving thing on account of his reference frame by dividing the time in our reference frame with $(1-\frac{V^2}{C^2})^{\frac {1}{2}}$.

Hence $V=C$ for light we get $0$ as denominator as this is my problem.

Well, we determine the travel time of moving thing on account of his reference frame by dividing the time in our reference frame with $(1-\frac{V^2}{C^2})^{\frac {1}{2}}$.

Hence $V=C$ for light we get $0$ as denominator as this is my problem.

Last edited by sourav das on Sat Apr 14, 2012 10:07 pm, edited 1 time in total.

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### Re: Age of Light

you are right. That's why there is not such thing as "light's reference frame". It does not exist. Reference frames are only defined for things moving slower than light.