Dhaka Junior 2011/8

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Dhaka Junior 2011/8

Unread post by Moon » Wed Feb 02, 2011 8:26 am

8. Abir started at $9:30$ pm from his house to go to Nayel’s house. When he reached there, he saw it was $8:55$ pm in Nayel’s clock. He started back towards his house when it was $9:00$ pm at Nayel’s. He reached at his house when it was $10:15$ pm in his clock. If Abir needed equal time to go and come back, find out the number of minutes Nayel’s clock is slow by.
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Mehfuj Zahir
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Re: Dhaka Junior 2011/8

Unread post by Mehfuj Zahir » Wed Feb 02, 2011 11:31 am

55 minutes slow.

nowshin tasnim
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Re: Dhaka Junior 2011/8

Unread post by nowshin tasnim » Wed Dec 14, 2011 1:20 pm

Mehfuj Zahir wrote:55 minutes slow.
please show method .

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Re: Dhaka Junior 2011/8

Unread post by nafistiham » Mon Dec 19, 2011 1:54 pm

the total time abir took is $9:30-8:55=45$ minutes.in it he stayed $5$ minutes in nayel's house. so he needs $20$ minutes to reach nayel's house.so, when he reaches nayel's house abir's clock said it was $9:50$ when nayel's clock it was $8:55$
so his clock is $55$ minutes slow
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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