### Dhaka Secondary 2009/4

Posted:

**Fri Jan 21, 2011 6:14 pm**\[( 1-\frac{1}{2^2} ) ( 1- \frac{1}{3^2} ) ( 1- \frac{1}{4^2} ) ( 1- \frac{1}{5^2} ) (1- \frac{1}{6^2} ) \cdots (1- \frac{1}{1000^2} ) =?\]

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Posted: **Fri Jan 21, 2011 6:14 pm**

\[( 1-\frac{1}{2^2} ) ( 1- \frac{1}{3^2} ) ( 1- \frac{1}{4^2} ) ( 1- \frac{1}{5^2} ) (1- \frac{1}{6^2} ) \cdots (1- \frac{1}{1000^2} ) =?\]

Posted: **Thu Jan 27, 2011 1:11 pm**

Nice problem ..

Posted: **Thu Aug 25, 2011 2:23 am**

I found a sequence out of the serial multiplications, my result is $\frac{1001}{2000}$

I just observed the multiplications of first 7 numbers, please check it though

I just observed the multiplications of first 7 numbers, please check it though

Posted: **Sat Feb 01, 2014 12:43 am**

What sequence did you find?