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Dhaka Secondary 2009/9
Posted: Fri Jan 21, 2011 6:19 pm
by BdMO
In a chess competition there are $101$ players and each of them is fixture to play one match with each of the rest. But one player got sick and could not play any match. At most how many players could play all the matches?
Re: Dhaka Secondary 2009/9
Posted: Tue Jan 25, 2011 1:18 pm
by leonardo shawon
$(100)^2 = 10000$
Re: Dhaka Secondary 2009/9
Posted: Tue Jan 25, 2011 7:23 pm
by Sudip Deb
100 . Because there are 100 players who will play with each other . The question is not how many match played but how many player play all the match.
Re: Dhaka Secondary 2009/9
Posted: Thu Jan 27, 2011 10:31 am
by Zzzz
Doesn't 'All' matches include the match against the 'sick player' ? Then the answer should be 0 !!
Re: Dhaka Secondary 2009/9
Posted: Thu Jan 27, 2011 1:24 pm
by leonardo shawon
Zzzz wrote:Doesn't 'All' matches include the match against the 'sick player' ? Then the answer should be 0 !!
the sick player couldnt play any matches. So they asked.. How many player could play all the matches! Isnt it?
Re: Dhaka Secondary 2009/9
Posted: Thu Jan 27, 2011 8:30 pm
by Tahmid Hasan
i got confused too
Re: Dhaka Secondary 2009/9
Posted: Thu Jan 27, 2011 9:13 pm
by leonardo shawon
the question was how many players could play all the matches... They didnt ask for WITH WHOM.. Just how many.. Am i confusing you guys??? I'm sorry if i can't.
Re: Dhaka Secondary 2009/9
Posted: Thu Aug 25, 2011 6:15 pm
by Shifat
I think the ans is 0, since the sick player is absent none will be able to play with him, so no other player will play full 100 matches, they all ahve to play 99, isnt it???
Re: Dhaka Secondary 2009/9
Posted: Fri Aug 26, 2011 10:28 pm
by leonardo shawon
yes the answer is zero.. I got confused too...
Re: Dhaka Secondary 2009/9
Posted: Fri Aug 26, 2011 10:38 pm
by Shifat
LOL.......