## Rangpur Secondary 2011/8

Problem for Secondary Group from Divisional Mathematical Olympiad will be solved here.
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Moon
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### Rangpur Secondary 2011/8

Problem 8:
Four points are chosen in the order $A$, $B$, $C$, $D$ on a line such that there is a point $X$, not on that line, so that triangles $XAB$ and $XCD$ have the same area. If $AB = 8$ and $BC = 5$, find the length $AD$.
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Tahmid Hasan
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Joined: Thu Dec 09, 2010 5:34 pm
the area and height(as they have the same vertex $X$) of $\delta XAB$ and $\delta XCD$ are same so $CD=8$
so $AD=AB+BC+CD=8+5+8=21$