Where did Diophantine go now, huh!

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rakeen
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Where did Diophantine go now, huh!

Unread post by rakeen » Fri Dec 17, 2010 4:35 pm

check this out.
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Moon
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Re: Where did Diophantine go now, huh!

Unread post by Moon » Fri Dec 17, 2010 10:50 pm

I believe you want to solve \[x^2+y^3=1 \text{ and } x+y^2=1\]
We have $x=1-y^2$. So, $(1-y^2)^2+y^3=1 \iff y^4-2y^2+y^3=0 \iff y^2(y^2+y-2)=0$
Do the rest yourself. :)
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rakeen
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Re: Where did Diophantine go now, huh!

Unread post by rakeen » Sat Dec 18, 2010 10:13 am

thnx :)
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